** Introduction: **

** * Digit: **Full numbers from 0 to 9 are called numbers.**
* Mixed Number:** The sum of the whole numbers and the differences is called the Mixed Number.

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**Noble Suggestion: – **About 7 questions related to addition and subtraction in the BANK CLERICAL exams are asked. In this, 5 questions are related to the whole number and 2 questions of the Mixed Number. More questions have to be resolved in less time in the competition examinations. Therefore, for the time being, efforts should be made to solve the problems based on addition and subtraction only through mental action.

** Tricks with Trickily Solved Examples **

** A ADDITION AND SUBTRACTION OF MIXED NUMBERS: **

**TRICK ⇒** complete numbers are added together or separated together and the fractions are added together. But if the sum of fractions comes in the form of a composite number then the whole number in it is added to the sum of the whole numbers.

** TYPE-1 **

** TRICK-** If the number of equal number (denominator) in the sum of the given combined number is present then the whole numbers are combined together and the equal fractions are added together.

** TYPE – 2 **

** TRICK⇒ **If there are two or more such different presentations in connection with the related joint and subtraction related to the United States, those who add and subtract ‘1’. Otherwise, such fractions are added and subtracted simultaneously.

** TYPE-3 **

** TRICK ⇒** If there are two or more such variables present in the questions related to the combination and subtraction associated with the combined number, those who add ” 0 ” on the addition and subtract, then such variations are added together and subtracted goes.

** TYPE-4 **

** TRICK ⇒ **If there are different types of questions in relation to the combined joint and subtraction questions, then the whole numbers are added together and the variations are added together and the same.

** TYPE-5 **

** TRICK ⇒ **If solving the questions based on combined numbers together, when the negative numbers of negative numbers (Negative value) decreases below 1 when the whole numbers are added together or decreased together, then the sum of the whole numbers ‘1’ is separated with the plus sign (+) and the fraction of it is reduced.

** B ADDITION AND SUBTRACTION OF WHOLE NUMBERS **

** TRICK ⇒ **The number of units, ten, hundredths, thousand and ten thousand in the expression given in the questions related to the combined and subtotal related to the whole numbers were added simultaneously and Is deducted. The unit number obtained from the sum of the digits of the unit is placed at the place of the unit for that expression and the remaining number is added to the sum of the tenth digit. Again, the unit number of the sum of the digits of the tenth digit is placed at the place of tens for that expression and the remaining number is added to the sum of hundreds of digits. In the end, similar actions are also continued to get the sum of the expression.

** Example:** 57432 + 2346 + 785 + 34 =?

** Explanation:
1st step. **(2 + 6 + 5 + 4) = [1] 7 ⇒ numerals of the unit of sum = 7

2nd step.

3rd step.

4th step.

5th step.

** TYPE – 1 **

** TRICK ⇒ **If the sum of the addition and subtraction of an expression is given to do the same, the largest positive number of the numbers present in it is assumed to be the basis. If after adding or subtracting the digits of the units of the remaining numbers, if the positive number is obtained then it is added to the number of units of the number assumed, and if negative. If the number is received, then the number of units of the number considered as the base. Is reduced. If the unit number of the assumed number is small and the negative number is large, then the unit number of the base is raised by negative number and then negative number of it is reduced. This type of action is also done for tens of ten, hundredths, thousand and ten thousand respectively.

** Example: **75653 – 43264 + 3246 – 7535 + 78 =?

** Explanation: **Basis = [7] [5] [6] [5] [3]

1st step. (-4 + 6 – 5 + 8) = 5 ⇒ [3] + 5 = 8,

∴ Points of the unit of expression = 8

2nd step (-6 + 4 – 3 + 7) = 2 ⇒ [5] + 2 = 7,

∴ Digimon’s tenth digit = 7

3rd step. (-2 + 2 – 5) = – 5 ⇒ [6] – 5 = 1,

∴ Number of hundreds of expressions = 1

4th step. (-3 + 3 – 7) = -7 ⇒15 – 7 = 8,

∴ 1000 points of expression = 8

last step. Digit of ten thousand expressions = (6-4) = 2

So the desired sum = 28178.

** TYPE-2. **

** TRICK ⇒ **If there are some numbers in the questions based on addition and subtraction = ‘on the left side and some numbers are on the right side of’ – ‘and (?), then with’ + sign (?) An action is taken to add and subtract the symbols of the numbers on the other side, that is, the ‘+ to (-) and’ – ‘as the “+” symbol.

** Example:** 57543 ー 2346 +? = 85432

** Explanation:** Base = [8] [5] [4] [3] [2]

1st step. (-3 + 6) = 3 ⇒ [2] – 3 = 5,

∴ Points of the unit of expression = 5

2nd step. (-4 + 4) = 0 ⇒ [3] + 0 = 3,

∴ Digimon’s tenth digit = 3

3rd step. (-5 + 3) = -2 ⇒ [4] -2 = 2.

∴ Points of hundreds of expressions = 2

4th step. (-7 + 2) = – 5 ⇒ [5] – 5 = 0,

∴ 1000 points of expression = 0

last step. [8] – 5 = 3

∴ Ten thousand points = 3

∴ ? = 30235 Ans.

** TYPE-3 **

** TRICK ⇒** If there are some numbers in the questions based on addition and subtraction ‘=’ on the left side of the sign and some numbers are on the right side of this sign and (?), (-) with the sign (? ), The action of adding and subtracting the symbol of the numbers on the opposite side is considered as reversed (i.e.) (-) and (-) as (+).

** Example **– 94532 – 6754 -? = 75432 – 2346

** Explanation :** Base = 8 13 14 13

[9] [4] [5] [3] [2]

1st step. (- 4-2 + 6) = 0 ⇒ [2] + 0 = 2,

∴ Points of the unit of expression = 2

2nd step (-5 -3 + 4) = -4 ⇒ (13-4) = 9

∴ ten digits of the expression = 9

3rd step (- 7-4 + 3) = -8 ⇒ (14-8) = 6

∴ Number of hundreds of expressions = 6

4th step. (-6-5 + 2) = -9 ⇒ (13-9) = 4

∴ thousand points of expression = 4

last step (8-7) = 1

∴ 10 thousand points of expression = 1

**TYPE – 4 **

** TRICK ⇒ **If the total numbers present in the question of any addition are made of the same number of repetitions and the first, second, third, and fourth numbers are respectively one, two, three and four digits respectively When doing a repetition, the number obtained by multiplying by 4 3 2 and 1, respectively, is placed at the place of unit, ten, hundredth and thousand of sum, respectively, as well as its carry. In the left hand side E is.

** Example :** 6666 + 666 + 66 + 6 =?

** Explanation : **

** 1st step.** 4 × 6 = [2] 4 ⇒ numeral units = 4

2nd step.

3rd step.

Last step.

** TYPE – 5 **

** C. ADDITION of DECIMAL **

** TRICK ⇒ **If the total numbers present in the sum of decimal numbers are made of the same number of iterations and the first, second, third, and fourth numbers respectively after decimal, one, two, three and four digits However, while solving these questions, by repeating one digit repetition multiplied by 1 2 3 and 4 respectively, the unit points of the product obtained are kept at the place of unit, ten, hundredths and thousand respectively. As well as achieved, it is added to your left hand digit. In the end, the decimal is placed after the four digits on the right side of the sum.

** Example :** 0.9999 + 0.999 + 0.99 + 0.9 =?

** Explanation : **

**1st step. **9 × 1 = 9 ∴ Sum of the unit of sum = 9**
2nd step.** 9 × 2 = [1] 8 का The digit of the tenth = 8,

3rd step.

4th step.

last step.

∴ ? = 3.8889 Ans.

** TYPE-6 **

Before solving the questions based on the addition and subtraction of decimal numbers, the number of decimal numbers is equal to the maximum number after the decimal in the total number of those present, after zero decimal (0) is equalized . After this, the action of addition and subtraction is taken.

** Example: **43.632 + 3.05 + 437.102 – 232.56 =?**
Explanation: **? = 43.632 + 3.050 + 437.102 – 232.560

Base = [4] [3] [7] [1] [0] [2]

1st step. (2 + 0 – 0) = [2] ⇒ 2 + 2 = 4

∴ Number of unit of sum = 4

2nd step. (3 + 5-6) = 2 ⇒ [0] + 2 = 2

∴ Number of tenths of the sum = 2

3rd step. (6 + 0 – 5) = 1 ⇒ [1] + 1 = 2

∴ Number of hundreds of sums = 2

4th step. (3 + 3 – 2) = 4 ⇒ [7] + 4 = [1] +1

∴ Number of thousandths of the sum = 1

5th step. (4-3) = 1 ⇒ [3] + [1] + 1 = 5

∴ Number of ten thousand of sum = 5

last step. Number of lakhs of sum = (4-2) = 2

∴ ? = 251.224 Ans.

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